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Determine an AP whose third term is 9 and when fifth term is subtracted from 8th term, we get 6. |
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Answer» Here given, a3 = 9 ⇒ a + 2d = 9 ....(i) a8 – a5 = 6 ⇒ (a + 7d) – (a + 4d) = 6 ⇒ 3d = 6 ⇒ d = 2 ....(ii) Substituting (ii) in (i), we get ⇒ a + 2(2) = 9 ⇒ a = 5 So, AP is 5, 7, 9, 11, ...... |
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