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InterviewSolution
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Determine γ from degree of freedom. |
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Answer» Suppose a polyatomic gas molecule has n degree of freedom. Total energy associated with one gram molecule of the gas, i.e., E = n × \(\frac{1}{2}\)RT × 1 =\(\frac{n}{2}\)RT As, Cv = \(\frac{d}{dT}\)€ = \(\frac{d}{dT}\)(\(\frac{n}{2}\)RT) = \(\frac{n}{2}\)R Cp = Cv + R Cp = \(\frac{n}{2}\)R + R = (\(\frac{n}{2}\)+1)R γ= \(\frac{C_p}{C_V}\) γ= \(\frac{(\frac{n}{2}+1)R}{\frac{n}{2}R}\) ∴ = \(\frac{2}{n}\)(\(\frac{n}{2}\)+1) γ= 1+\(\frac{2}{n}\) |
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