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Determine if the set A ={-1,1,3}is a proper subset of the set B={x:x in R and x^3-2x^2-x+2=0} |
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Answer» SOLUTION :Solving `x^3-2x^2-c+2=0` we have `x^2(x-2)-1(x-2)=0` or, `(x-2)(x^2-1)=0` `:.`x=1,-1,2` `:. B ={-1,1,2}` `:.`A is not a subset of B. |
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