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Determine LP+ LQ+LR+ LS+ LT.24(a) 4 right angle(c) 2 right angle(b) 3 right angle(d) 6 right angle

Answer»

Bylinearpairaxiomwehave,∠DEP=180-∠5∠EDP=180-∠4In△PDE,sumofallangleswillbe180.⇒∠P+180-∠5+180-∠4=180⇒∠P=∠5+∠4-180Similarly∠Q=∠5+∠1-180∠R=∠1+∠2-180∠S=∠2+∠3-180∠T=∠3+∠4-180Addingabove5equations,weget,∠P+∠Q+∠R+∠S+∠T=2∠1+∠2+∠3+∠4+∠5-900InpentagonABCDE,∠1+∠2+∠3+∠4+∠5=540⇒∠P+∠Q+∠R+∠S+∠T=2540-900=1080-900⇒∠P+∠Q+∠R+∠S+∠T=180= 2 right angleAnswer



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