1.

Determine the amount of Calcium Chloride dissolved in 2.5 litre of water that it's osmotic pressure is 0.75 atm. temperature is 27°CVann Hoff factor is 2.47​

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EXPLANATION:

Solution

Given that

Osmotic pressure π = 0.75 atm

Volume V = 2.5 liter

van’t Hoff factor i = 2.47

T = 27 + 273 = 300 K

Let w is the amount of CaCl2 required

Gas constant R = 0.0821 L atm K-1mol-1

Molar mass of CaCl2M = 1 × 40 + 2 × 35.5 = 111g mol-1

Use the formula of osmotic pressure

Plug the values in this formula we get

W = 3.43 g

Answer

Required amount of CaCl2 = 3.42 g.



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