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Determine the amount of Calcium Chloride dissolved in 2.5 litre of water that it's osmotic pressure is 0.75 atm. temperature is 27°CVann Hoff factor is 2.47 |
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Answer» Solution Given that Osmotic pressure π = 0.75 atm Volume V = 2.5 liter van’t Hoff factor i = 2.47 T = 27 + 273 = 300 K Let w is the amount of CaCl2 required Gas constant R = 0.0821 L atm K-1mol-1 Molar mass of CaCl2M = 1 × 40 + 2 × 35.5 = 111g mol-1 Use the formula of osmotic pressure
Plug the values in this formula we get
W = 3.43 g Answer Required amount of CaCl2 = 3.42 g. |
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