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Determine the AP whose third term ıs l 6 and the 7th term exceeds te fit termi |
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Answer» Let a be the First term, a3 be the third term, a5 be the 5th term and a7 be the 7th term a3 = 16 a7 = a5 + 12 ............ (1) Let the common difference be "d" Common difference is equal in AP So, a7 = a5 + d + d = a5 + 2d............(2) From Equation (1) & (2) a5 + 12 = a5 + 2d 2d = 12 d = 6 From Given, we get that a3 = 16 a3 = a + 2d = 16 a + ( 2× 6 ) = 16 [ We know that d = 6 ] a + 12 = 16 a = 4 So first term is 4 .... We can find AP by adding d continuously So,AP is 4, 10, 16, 22, 28..... |
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