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    				| 1. | Determine the binding energy of satellite of mass `1000 kg` revolving in a circular orbit around the Earth when it is close to the surface of Earth. Hence find kinetic energy and potential energy of the satellite. [Mass of Earth `=6xx10^(24)kg`, radius of Earth `=6400km`, gravitational constant `G=6.67xx10^(-11)Nm^(2)//kg^(2)`] | 
| Answer» Given: Mass of satellite, `m=1000kg` Mass of earth, `M_(e)=6xx10^(24)kg` Radius of earth, `R_(e)=6400km` `=6.4xx10^(6)` metre Gravitational constant, `G=6.67xx10^(-11)Nm^(2)//kg^(2)` Binding energy of satellite`=?` Kinetic energy and potential energy of satellite `=?` Binding energy of satellite close to the surface of earth is given by Binding energy `=+-(1)/(2)*(GM_(e)m)/(R_(e))` `=(1)/(2)xx(6.67xx10^(-11)xx6xx10^(24)xx1000)/(6.4xx10^(6))` `=3.1265xx10^(10)J` Kinetic energy, `K.E.=(1)/(2)*(GM_(e)m)/(R_(e))` `K.E.=3.1265xx10^(10)J` Potential energy, `P.E.=-(GM_(e)m)/(R_(e))` `:.P.E.=-2K.E.` `P.E.=-6.2530xx10^(10)J` | |