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Determine the centre of gravity of plane lamina by pivoting method.

Answer» <html><body><p></p>Solution :We can <a href="https://interviewquestions.tuteehub.com/tag/determine-437910" style="font-weight:bold;" target="_blank" title="Click to know more about DETERMINE">DETERMINE</a> the centre of gravity of a uniform lamina of even an <a href="https://interviewquestions.tuteehub.com/tag/irregular-2749380" style="font-weight:bold;" target="_blank" title="Click to know more about IRREGULAR">IRREGULAR</a> shape by pivoting it at <a href="https://interviewquestions.tuteehub.com/tag/various-1443317" style="font-weight:bold;" target="_blank" title="Click to know more about VARIOUS">VARIOUS</a> points by trial and error. The lamina remains horizontal when pivoted at a point. The net gravitatioinal force acts at the point. It is the centre of gravity as shown in the figure. <br/> When a body is supported at the centre of gravity, the sum of the torques acting on all the point <a href="https://interviewquestions.tuteehub.com/tag/masses-1088822" style="font-weight:bold;" target="_blank" title="Click to know more about MASSES">MASSES</a> of the rigid body becomes <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a>. in addition the weight is compensated by the normal reaction force exerted by the pivot. The body is in static equuilibriu. Hence it remains horizontal. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C05_E02_122_S01.png" width="80%"/></body></html>


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