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Determine the centroid of the wire shown in Fig. |
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Answer» The wire is divided into three segments AB, BC and CD. Taking A as origin the coordinates of the centroids of AB, BC and CD are G1(300, 0); G2(600, 100) and G3 (600 – 150 cos 45°, 200 + 150 sin 45°) i.e., G3 (493.93, 306.07) L1 = 600 mm, L2 = 200 mm, L3 = 300 mm ∴ Total length L = 600 + 200 + 300 = 1100 mm ∴ From the eqn. Lxc = ΣLi xi , we get 1100 xc = L1x1 + L2x2 + L3x3 = 600 × 300 + 200 × 600 + 300 × 493.93 ∴ xc = 407.44 mm Lyc = ΣLi yi 1100 yc = 600 × 0 + 200 × 100 + 300 × 306.07 ∴ yc = 101.66 mm |
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