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Determine the concentration of `CO_(2) " which will be in equilibrium with " 2* 5 xx 10^(-2) mol L^(-1) " of CO at "100^(@)C " for the reaction, " FeO(s) + CO (g) hArrFe (s) + CO_(2) (g) , K_(c) = 5*0` |
Answer» `K_(c) = ([CO_(2)])/([CO]) , i.e.,5 = ([CO_(2)])/(2*5 xx 10^(-2)) or [CO_(2)] = 5 xx 2*5 xx 10^(-2) = 12*5 xx 10^(-2) mol L^(-1)` | |