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Determine the empirical formula `(EF)` of the oxide of chomium containing `68.4% Cr` by mass.A. `Cr O_(3)`B. `Cr_(2) O_(3)`C. `Cr O_(5)`D. `Cr_(3) O_(4)` |
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Answer» Correct Answer - B `n_(Cr) = (68.4g)/(52g mol^(-1)) = 1.32, n_(O) = (31.6g)/(16g mol^(-1)) = 1.98` `(n_(Cr))/(n_(O)) = (1.32)/(1.98) = (132)/(198) = (2xx66)/(3xx66) = (2)/(3)` `:. EF` is `Cr_(2) O_(3)`. |
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