Determine the empirical formula of an oxide of iron which has 69.9% ir – InterviewSolution

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1.

Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass

Answer»

Element	%	Atomic mass	Relative no. of atoms	Simplest ratio	Whole number ratio
Iron	69.9	56	69.9/56 = 1.25	1.25/1.25 = 1	2
dioxygen	30.0	16	30.1/16 = 1.89	1.89/1.25 1.5	3

Empirical formula = Fe₂O₃

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