Determine the empirical formula of an oxide of iron which has 69.9℅ iron and 30.1℅ dioxygen by mass.

Determine the empirical formula of an oxide of iron which has 69.9℅

1.	Determine the empirical formula of an oxide of iron which has 69.9℅ iron and 30.1℅ dioxygen by mass.
Answer» Iron:% by mass= 69.9Atomic mass= 55.85Moles of element( relative no. of moles)= 69.9/55.85 = 1.25Simplest molar ratio = 1.25/1.25 = 1Simplest whole no. molar ratio= 2Oxygen:% by mass = 30.1Atomic mass = 16.00Moles of element =30.1/16.00 = 1.88Simplest molar ratio = 1.88/1.25 = 1.5Simplest whole no. molar ratio = 3Fe2O3