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Determine the maximum acceleration of the trainin which a box lying on itsfloor will remain stationary given that the coefficeient of static friction between the box and the train 's floor is 0.15 takeg=10ms^(-2) |
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Answer» Solution :As the accelerationof the BOS ix due to staticfriction so ma `=F le mu_(s) R = mu_(3) mg` `:.,a = mu_(s) g` or `a_(MAX)=mu_(s) g= 0 .15xx 10= 1.5 MS^(-2)` |
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