1.

Determine the maximum acceleration of the trainin which a box lying on itsfloor will remain stationary given that the coefficeient of static friction between the box and the train 's floor is 0.15 takeg=10ms^(-2)

Answer»

Solution :As the accelerationof the BOS ix due to staticfriction so
ma `=F le mu_(s) R = mu_(3) mg`
`:.,a = mu_(s) g`
or `a_(MAX)=mu_(s) g= 0 .15xx 10= 1.5 MS^(-2)`


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