1.

Determine the molecular formula of an oxide in which mass percent of iron and oxygen are 69.9 and 30.1 respectively.

Answer»
Element%Atomic
mass
Relative no.
of atoms
Simplest
ratio
Whole number
ratio
Iron69.95669.9/56 = 1.251.25/1.25 = 12
dioxygen30.11630.1/16 = 1.891.89/1.25 1.53

Empirical formula = Fe2O3

Molecular formula = Fe2O3



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