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Determine the molecular formula of an oxide of iron in which the mass per cent of iron and oxygen are 69.9 and 30.1 respectively. |
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Answer» Empirical formula `=Fe_(2)O_(3)` `=2xx56+3xx16` `=160` `n=("MOLECULAR mass")/("Empirical formula mass")` `=(160)/(160)=1` Molecular formula `=n xx ` emplirical formula Molecular formula `= n xx` emplirical formula `=1xx(Fe_(2)O_(3))` `=Fe_(2)O_(3)` |
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