1.

Determine the molecular formula of an oxide of iron in which the mass per cent of iron and oxygen are 69.9 and 30.1 respectively.

Answer»



Solution :
Empirical formula `=Fe_(2)O_(3)`
`=2xx56+3xx16`
`=160`
`n=("MOLECULAR mass")/("Empirical formula mass")`
`=(160)/(160)=1`
Molecular formula `=n xx ` emplirical formula
Molecular formula `= n xx` emplirical formula
`=1xx(Fe_(2)O_(3))`
`=Fe_(2)O_(3)`


Discussion

No Comment Found