1.

Determine the number of moles of Agl which may be dissolved in 1.0 litre of 1.0M CN^(-)solution ,K_(sp)for Agl and K_ffor [ Ag (CN)_2]^(-)" are "1.2 xx 10 ^(-17)M^(2) and 7. 1 xx 10 ^(-19)respectively. If answer is 4.9 xx 10 ^(x)then x =__________?

Answer»


Solution :`Agl hArr Ag^(+) I^(-),KSP`
` (Ag^(+) +2CN^(-)hArr [Ag(CN)_2]^(-),K_f)/( underset( 1-2s) (Agl)+2CN^(-)hArr [Ag(CN)_2]^(-)+I^(-),K =KspK_f) `
` ((s)/(1-2s) )^(2)=Ksp, K_f =1.2 xx 10^(-17)xx 7.1 xx 10 ^(19) `
` rArr (s)/( 1-2s)=SQRT(8.52 xx 10 ^(2)) =29`
` 59S =29 rArr S =0.49 rArr S = 4.9 xx 10 ^(-1) `


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