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Determine the potential of the following cell: `Pt|H_(2)(g,0.1bar)|H^(+)(aq,10^(-3)M)| |` `MnO_(4)^(-)(aq,0.1M),Mn^(2+)(aq,0.01M),` `H^(+)(aq.0.01M)|Pt` Given :`E_(MnO_(4)^(-)|Mn^(2+))^(0)=1.51V`A. `1.54V`B. `1.48V`C. `1.84V`D. `1.51` |
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Answer» Correct Answer - B Anode `H_(2(g))rarr2H^(+)(aq)+2e^(-)` (i)Cathode `MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O` (ii) `(i)xx(5)` `(ii)xx(2)` `E=E^(o)-(0.06)/(10)log,([Mn^(2+)]^(2)[H^(+)]_(a)^(10))/([MnO_(4)^(-)][H^(+)]_(ca)^(16)P_(H2)^(5))` `=1.51-(0.06)/(10)log,((10^(-2))^(2)xx(10^(-3))^(10))/((10^(-1))^(2)xx(10^(-2))^(16)(10^(-1))^(5))` `=1.51-(0.06)/(10)log10^(5)` `=1.51-0.03=1.48V` |
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