Determine the power content of the carrier an each of side bands of an

1.	Determine the power content of the carrier an each of side bands of an AM wave having a percent modulation of 80% and a total power of 2200W.
Answer» m_a = 80% = \(\frac{80}{100}\) = 0.8 P_T = 2200 W P_T = P_c(1 + \(\frac{m_a^2}{2}\)) 2200 = P_c[1 + \(\frac{(0.8)^2}{2}\)] 2200 = P_c[1 + 0.32] P_c = \(\frac{2200}{1.32}\) P_c= 1666W P_T = P_c+ Power in the sidebands Power in two sidebands = P_T - P_c = 2200 - 1666W = 534W Power in each sideband = \(\frac{534}{2}\) = 267W

Determine the power content of the carrier an each of side bands of an AM wave having a percent modulation of 80% and a total power of 2200W.

Answer»

m_a = 80%

= \(\frac{80}{100}\)

= 0.8

P_T = 2200 W

P_T = P_c(1 + \(\frac{m_a^2}{2}\))

2200 = P_c[1 + \(\frac{(0.8)^2}{2}\)]

2200 = P_c[1 + 0.32]

P_c = \(\frac{2200}{1.32}\)

P_c= 1666W

P_T = P_c+ Power in the sidebands

Power in two sidebands = P_T - P_c

= 2200 - 1666W

= 534W

Power in each sideband = \(\frac{534}{2}\)

= 267W