Determine the probability when a die is thrown 2 times such that there are no fours and no fives occur?(a) \(\frac{4}{9}\)(b) \(\frac{56}{89}\)(c) \(\frac{13}{46}\)(d) \(\frac{3}{97}\)This question was addressed to me in examination.My question comes from Counting in section Counting of Discrete Mathematics

Determine the probability when a die is thrown 2 times such that there

1.	Determine the probability when a die is thrown 2 times such that there are no fours and no fives occur?(a) \(\frac{4}{9}\)(b) \(\frac{56}{89}\)(c) \(\frac{13}{46}\)(d) \(\frac{3}{97}\)This question was addressed to me in examination.My question comes from Counting in section Counting of Discrete Mathematics
Answer» Right OPTION is (a) \(\frac{4}{9}\) To explain: In this experiment, throwing a die ANYTHING other than a 4 is a success and ROLLING a 4 is failure. SINCE there are two trials, the required probability is b(2; 2, \(\frac{5}{6}\)) = ^2C2 * (\(\frac{4}{6}\))^2 * (\(\frac{2}{6}\))^0 = \(\frac{4}{9}\).

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