1.

Determine the radius of a drop of water falling through air, if it covers 0-048 min 4 s with a uniform velocity. Assume the density of air as 0-00121 gm/cc and eta =1.8 xx 10^(5) Ns m^(-2).

Answer»


Solution :` a= [9 eta v //2 (rho - SIGMA )g]^(1//2)= sqrt(9xx 1.8 xx 10 ^(-5)xx ( 0.048//4 ) //2 (1000 -1-.21)xx 9.8 ) = 9.96 xx 10 ^(-6)m `


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