Determine the rate law for first order reaction 2A → R at constant pressure with 60% A in the initial reaction mixture and reduces by 15% in 4 minutes.(a) -rA = 0.17 CA(b) -rA = CA(c) -rA = 2CA(d) -rA = 3.6CAI had been asked this question in an online quiz.My doubt stems from Batch Reactor Design Equations in division Ideal Reactors for a Single Reaction, Conversion and Reactor Sizing of Chemical Reaction Engineering

Determine the rate law for first order reaction 2A → R at constant p

1.	Determine the rate law for first order reaction 2A → R at constant pressure with 60% A in the initial reaction mixture and reduces by 15% in 4 minutes.(a) -rA = 0.17 CA(b) -rA = CA(c) -rA = 2CA(d) -rA = 3.6CAI had been asked this question in an online quiz.My doubt stems from Batch Reactor Design Equations in division Ideal Reactors for a Single Reaction, Conversion and Reactor Sizing of Chemical Reaction Engineering
Answer» The correct option is (a) -RA = 0.17 CA For explanation I would say: 2A → R εA = \(\frac{.7-1}{1}\) = -0.3 \(\begin{array}{c\|c c} & X_A=0 & X_A = 1 \\ \hline A & 0.6 & 0.3 \\ I & 0.4 & 0.4 \\ \hline & 1 & 0.7 \\ \END{array} \) ΔV = V-Vo = Vo – 0.15 VO – VO = -0.15 VO -ln(1-\(\frac{ΔV}{Vo εA}\)) = kt => k = 0.173 min^-1.

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