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Determine the shapes of the given molecules or ions: (1) POCl_(3) (2) CH_(3)^(-) |
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Answer» SOLUTION :(1) P-atom in `POCl_(3)` molecule is attached to the O-atom by a double bond and to three Cl-atoms by three SINGLE bonds. The number of electrons in the valence shell of P-atom =5+2+1+1+1=10. out of these 10 electrons or 5 electron pairs, 1 electron pair is involved in formation of a `pi`-bond which have no role in determining the SHAPE of the molecule. according to VSEPR theory, four electron pairs are oriented tetrahedraly, i.e., shape of the molecule is tetrahedral. (2) C-atom in `CH_(3)^(-)` ion is bonded to three H-atoms by three single bonds. the number of electrons in the valence shell of C-atom =4+3+1 (for the negative CHARGE)=8. out of these 8 electrons or 4 electron pairs, there are three bond-pairs and one lone-pair. According to VSEPR theory, the ion is pyramidal. |
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