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Determine the values of all the four quantum numbers of the 8^(th) electron in O-atom and 15^(th) electron in CI atom . |
Answer» SOLUTION :Electronic configuration of oxygen= `:. 8^(th)` electron PRESENT in `2p_(x)` ORBITAL and the quantum number are `n = 2, l = 1 , m_1 = "either" + 1 "or" - 1 and s = -1//2` Electronic configuration of chlorine = `15^(th)` electron present in `3P_z` orbital and the quantum numbers are `n = 3, l = 1, m_1= ` either + 1or - 1 and ms = + 1//2. |
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