1.

Determine their present ages. The sum of the ages of two friends is 20 years. Four years ago, the product of their ages in years was 48.

Answer» let the age of 1 be`x`
le the age of 2 be `y`
acc to question
`x+y= 20`
& `(x-4)(y-4) = 48`
`xy-4x-4y+16=48`
`xy-4(x+y) = 32`
`xy-4(20) = 32`
`xy-80=32`
`xy=112`
`x+ 112/x = 20`
`x^2- 20x +112=0`
D`=b^2-4ac`
`=(-20)^2 - 4(112)`
`=-48`
age can not be imaginary and negative so solution is not possible.


Discussion

No Comment Found

Related InterviewSolutions