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Determine total energy of 1 mol of photons in J/mol having λ = 600 nm Given h = 6.62 × 10-34J-sec, c = 3 x 108 ms1(1) 1.99 × 105 J/mol (2) 6.64 x 108 J/mol (3) 1.24 × 104 J/mol(4) 1.24 × 108 J/mol |
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Answer» Correct option is (1) 1.99 x 105 J/mol \(E_T = \frac{N_AhC}{\lambda}\) \(E_T = \frac{6.02 \times 10^{23}\times 6.62 \times 10^{-34}\times 3 \times 10^8}{600\times 10^4}\) \(= \frac{119.56 \times 10^{-3}}{600\times 10^{-9}}\) \(= 19.93 \times 10^4J/mol\) or 1.99 x 105 J/mol |
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