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Determine two consecutive multiples of 3 whose product is 270. |
Answer» Let the consecutive multiples of 3 be a, a + 3 ⇒ a(a + 3) = 270 ⇒ a2 + 3a – 270 = 0 ⇒ a2 + 18a – 15a – 270 = 0 ⇒ a(a + 18) -15(a + 18) = 0 ⇒ (a – 15)(a + 18) = 0 ⇒ a = 15 Numbers are 15, 18 |
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