Determine whether the given values are solutions of the given equation

1.	Determine whether the given values are solutions of the given equation or not:x2 – 3x + 2 = 0 , x = 2 , x = – 1
Answer» Here we have, LHS = x²– 3x + 2 Substituting x = 2 in LHS, we get (2)²– 3(2) + 2 ⇒ 4 – 6 + 2 = 0 = RHS ⇒ LHS = RHS Thus, x = 2 is a solution of the given equation. Similarly, Substituting x = -1 in LHS, we get (-1)²– 3(-1) + 2 ⇒ 1 + 3 + 2 = 6 ≠ RHS ⇒ LHS ≠ RHS Thus, x = -1 is not a solution of the given equation.

Determine whether the given values are solutions of the given equation or not:x2 – 3x + 2 = 0 , x = 2 , x = – 1

Answer»

Here we have,

LHS = x²– 3x + 2

Substituting x = 2 in LHS, we get

(2)²– 3(2) + 2

⇒ 4 – 6 + 2 = 0 = RHS

⇒ LHS = RHS

Thus, x = 2 is a solution of the given equation.

Similarly,

Substituting x = -1 in LHS, we get

(-1)²– 3(-1) + 2

⇒ 1 + 3 + 2 = 6 ≠ RHS

⇒ LHS ≠ RHS

Thus, x = -1 is not a solution of the given equation.