Determine whether the given values are solutions of the given equation

1.	Determine whether the given values are solutions of the given equation or not:2x2 – x + 9 = x2 + 4x + 3, x = 2, x = 3
Answer» Here we have, 2x²– x + 9 = x²+ 4x + 3 ⇒ x²– 5x + 6 = 0 LHS = x²– 5x + 6 Substituting x = 2 in LHS, we get (2)²– 5(2) + 6 ⇒ 4 – 10 + 6 = 0 = RHS ⇒ LHS = RHS Thus, x = 2 is a solution of the given equation. Similarly, Substituting x = 3 in LHS, we get (3)²– 5(3) + 6 ⇒ 9 – 15 + 6 = 0 = RHS ⇒ LHS = RHS Thus, x = 3 is a solution of the given equation.

Determine whether the given values are solutions of the given equation or not:2x2 – x + 9 = x2 + 4x + 3, x = 2, x = 3

Answer»

Here we have,

2x²– x + 9 = x²+ 4x + 3

⇒ x²– 5x + 6 = 0

LHS = x²– 5x + 6

Substituting x = 2 in LHS, we get

(2)²– 5(2) + 6

⇒ 4 – 10 + 6 = 0 = RHS

⇒ LHS = RHS

Thus, x = 2 is a solution of the given equation.

Similarly,

Substituting x = 3 in LHS, we get

(3)²– 5(3) + 6

⇒ 9 – 15 + 6 = 0 = RHS

⇒ LHS = RHS

Thus, x = 3 is a solution of the given equation.