1.

Diagonals of the Rhombus are 6 cm and 8 cm, then find the perimeter of the Rhombus.1. 12 cm2. 16 cm3. 20 cm4. 24 cm

Answer» Correct Answer - Option 3 : 20 cm

GIVEN:

Diagonals of the Rhombus = 6 cm and 8 cm

FORMULA USED:

d12 + d22 = 4 × (a)2 Where d1 & d2 are the diagonals of the Rhombus and a is the side

CALCULATION:

Diagonals of the Rhombus = 6 cm and 8 cm

⇒ d12 + d22 = 4 × (a)2

⇒ 62 + 82 = 4 × (a)2

⇒ 100 = 4 × (a)2

⇒ 25 = (a)2

⇒ a = 5

⇒ Perimeter of the Rhombus = 4 × a

⇒ 4 × 5

⇒ 20

∴ Perimeter of the Rhombus is 20 cm



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