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Diagonals of the Rhombus are 6 cm and 8 cm, then find the perimeter of the Rhombus.1. 12 cm2. 16 cm3. 20 cm4. 24 cm |
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Answer» Correct Answer - Option 3 : 20 cm GIVEN: Diagonals of the Rhombus = 6 cm and 8 cm FORMULA USED: d12 + d22 = 4 × (a)2 Where d1 & d2 are the diagonals of the Rhombus and a is the side CALCULATION: Diagonals of the Rhombus = 6 cm and 8 cm ⇒ d12 + d22 = 4 × (a)2 ⇒ 62 + 82 = 4 × (a)2 ⇒ 100 = 4 × (a)2 ⇒ 25 = (a)2 ⇒ a = 5 ⇒ Perimeter of the Rhombus = 4 × a ⇒ 4 × 5 ⇒ 20 ∴ Perimeter of the Rhombus is 20 cm |
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