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Diameter of the moon is `3.5xx10^(3)km`and its distance from earth is`3.8xx10^(5)km`.It is seen by a telescope whose objectives and eyepiece have focal lengths`4`mand `10cm`respectively.The angular diameter fo the image of the moon will be nearly- (1) `5^(@)` ,(2) `10^(@)` ,(3)` 20^(@)` ,(4)`25^(@)` |
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Answer» `M=-(f_(0))/(f_(e))=-(400)/(10)-40` Angle substanded by the moon at the objective ` =(3.5xx10^(3))/(3.8xx10^(5))=0.009 radian` Thus the angular diameter of the image `=Mxx"visual angle"` `=40xx0.009=0.36radian` `=(0.36xx180)/(3.14)=20^(@)` |
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