Diameters of the arms of a U tube are 10 mm and 1 mm . It is partially filled with water and it is held in a vertical plane . Find the difference in heights of water in both the arms . (Surface tension of water =70 dyne cm^(-1) angle of contact =0^(@).g=980cms^(-2))

Diameters of the arms of a U tube are 10 mm and 1 mm . It is partially

1.	Diameters of the arms of a U tube are 10 mm and 1 mm . It is partially filled with water and it is held in a vertical plane . Find the difference in heights of water in both the arms . (Surface tension of water =70 dyne cm^(-1) angle of contact =0^(@).g=980cms^(-2))
Answer» SOLUTION :`r_(1)=(d_(1))/(2)=5mm=0.5cm` `r_(2)=(d_(2))/(2)=0.05cm` `T=70"dyne"//CM` `theta=0` `rho=1g//cm^(3)` `rho=1g//cm^(3)` `g=980cm//s^(2)` `T=(rhrhog)/(2costheta)` `thereforeh=(2Tcostheta)/(rrhog)` `thereforeh=h_(2)-h_(1)` `thereforeh=(2Tcostheta)/(rhog)[(1)/(r_(2))-(1)/(r_(1))]` `=(2xx70xxcos0^(@))/(1xx980)[(1)/(0.05)-(1)/(0.5)]` `=(1)/(7)[20-2]` `thereforeh=(18)/(7)=2.57//cm`