Diborane is a potential rocket fuel which undergoes combustion according to the reaction: B_(2)H_(6)(g) + 3O_(2)(g) to B_(2)O_(3)(s) + 3H_(2)O(g) From the following data, calculate the enthalpy change for the combustion of diborane. 2B(s) + 3/2O_(2)(g) to B_(2)O_(3)(s) DeltaH = -1273 kJ"mol"^(-1) H_(2)(g) + 1/2O_(2)(g) to H_(2)O(l)DeltaH =-286 kJ"mol"^(-1) H_(2)O(l) to H_(2)O(g)DeltaH = 44 kJ"mol"^(-1) 2B(s) + 3H_(2)(g) to B_(2)H_(6)(g)DeltaH = 36 kJ"mol"^(-1).

Diborane is a potential rocket fuel which undergoes combustion accordi

1.	Diborane is a potential rocket fuel which undergoes combustion according to the reaction: B_(2)H_(6)(g) + 3O_(2)(g) to B_(2)O_(3)(s) + 3H_(2)O(g) From the following data, calculate the enthalpy change for the combustion of diborane. 2B(s) + 3/2O_(2)(g) to B_(2)O_(3)(s) DeltaH = -1273 kJ"mol"^(-1) H_(2)(g) + 1/2O_(2)(g) to H_(2)O(l)DeltaH =-286 kJ"mol"^(-1) H_(2)O(l) to H_(2)O(g)DeltaH = 44 kJ"mol"^(-1) 2B(s) + 3H_(2)(g) to B_(2)H_(6)(g)DeltaH = 36 kJ"mol"^(-1).
Answer» SOLUTION :The EQUATION is : `B_(2)H_(6)(g) + 3O_(2)(g) to B_(2)O_(3)(s) + 3H_(2)O(g) DeltaH = ?` (i)`3B(s) + 3/2 O_(2)(g)to B_(2)O_(3)(s)DeltaH = -1273 kJ"mol"^(-1)` (ii)` H_(2)(g) + 1/2O_(2)(g) to H_(2)O(l)DeltaH = -286 kJ"mol"^(-1)` (iii) `H_(2)O(l) to H_(2)O(g)DeltaH = 44 kJ"mol"^(-1)` (iv)`2B(s) + 3H_(2)(g) to B_(2)H_(6)(g) DeltaH = 36 kJ"mol"^(-1)` Subtract eq.(iv) from eq.(i) (v) `B_(2)H_(6) (g) + 3/2O_(2)(g) to B_(2)O_(3)(s) + 3H_(2)(g)DeltaH = -1309 kJ"mol"^(-1)` MULTIPLY eq.(ii) by 3 (vi) `3H_(2)(g) + 3/2O_(2)(g) to 3H_(2)O(l)DeltaH = -858 kJ"mol"^(-1)` Add`B_(2)H_(6)(g) + 3O_(2)(g) to B_(2)O_(3)(s) + 3H_(2)O(l)DeltaH = -2167 kJ"mol"^(-1)` Multiply eq.(iii) by 3 (vii) `3H_(2)O(l) to 3H_(2)O(g)DeltaH = 132 kJ"mol"^(-1)` Add `B_(2)H_(6)(g) + 3O_(2)(g) to B_(2)O_(3)(s) + 3H_(2)O(g) Delta = -2035 kJ"mol"^(-1)`.