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Difference between the wave length of 1^(st) line of Balmer series and last line of Paschen series for Li^(2+) ion is 1/(xR_H) then .x. is |
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Answer» `1/(lambda_2) = R(1/(3^2) - 1/(alpha^2))9` On solving `(lambda_1)/(lambda_2) = 1/(5R)` |
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