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differential equation (2x + 3y) dx + (4x + y) dy = 0? |
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Answer» The given differential equation is (4x – 3y)dx + (2y – 3x)dy = 0 4xdx + 2ydy – 3(xdy + ydx) = 0 4xdx + 2ydy – 3d(xy) = 0 Integrating, we get 2x2 + y2 – 3xy = c which is the required solution of the given differential equation= |
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