Differential equation of x2= 4b(y + b), where b is a parameter, is(1)

1.	Differential equation of x2= 4b(y + b), where b is a parameter, is(1) x(dy/dx)2 = 2y(dy/dx) + x2(2) x(dy/dx)2 = 2y(dy/dx) + x(3) x(dy/dx)2 = y(dy/dx) + x2(4) x(dy/dx)2 = y(dy/dx) + 2x2
Answer» Answer is (2) x(dy/dx)² = 2y(dy/dx) + x 2x = 4by' ⇒ b = x/2y' So. differential equation is x² = 2x/y, . y + (x/y)² ⇒ x(dy/dx)² = 2y(dy/dx) + x

Differential equation of x2= 4b(y + b), where b is a parameter, is(1) x(dy/dx)2 = 2y(dy/dx) + x2(2) x(dy/dx)2 = 2y(dy/dx) + x(3) x(dy/dx)2 = y(dy/dx) + x2(4) x(dy/dx)2 = y(dy/dx) + 2x2

Answer»

Answer is (2) x(dy/dx)² = 2y(dy/dx) + x

2x = 4by' ⇒ b = x/2y'

So. differential equation is x² = 2x/y, . y + (x/y)²

⇒ x(dy/dx)² = 2y(dy/dx) + x

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Differential equation of x2= 4b(y + b), where b is a parameter, is(1) x(dy/dx)2 = 2y(dy/dx) + x2(2) x(dy/dx)2 = 2y(dy/dx) + x(3) x(dy/dx)2 = y(dy/dx) + x2(4) x(dy/dx)2 = y(dy/dx) + 2x2

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