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Differentiate.In (4x^2(2x-7)^3)/(3x^2-7)^5

Answer»

SOLUTION :`y =In (4x^2(2x-7))/(3x^2+7)`
`In 4+2In x+3In (2x-7)-5In(3x^2+7)`
`thereforedy/dx=2/x+6/(2x-7)-5/(3x^2+7)6X`
2/x+6/(2x-7)-(5X)/(3x^2+7)cdot6x`


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