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Differentiate (lnx)/x^2

Answer»

Solution :`y=lnx/x^2`
`(DY)/(dx)=(d/(dx)(lnx)cdotx^2-lnxcdotd/(dx)(x^2))/((x^2)^2)`
`=(1/xcdotx^2-lnxcdot2x)/x^4=(x-2xcdotlnx)/x^4`
`(1-2lnx)/(x^3)=(lne-lnx^2)/(x^3)=(LN(e/x^2)/x^3`


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