1.

Differentiate the following:6y = 9 log 3x

Answer»

y = 9 log 3x

\(\cfrac{dy}{d\text x}=\cfrac{9}{3\text x}\times\cfrac{d}{d\text x}3\text x\) 

\(\Big(\)\(\therefore\cfrac{d}{d\text x}log \text x=\cfrac1{\text x}\) and chain rule\(\Big)\)

\(=\cfrac{9}{3\text x}\times3\) = \(\cfrac9{\text x}\)



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