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Differentiate x^2log_2x+secx |
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Answer» SOLUTION :`y=x^2log_2x+SECX` `dy/dx=d/dx(x^2)cdotlog_2x+x^2cdotd/dx(log_2x)+d/dx(secx)` `=2X cdotlog_2x+x^2cdot1/xlog_2e+secx CDOT TANX` |
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