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| 1. |
Differentiate y=a^x |
| Answer» SOLUTION :`y=a^xlogy=koga^X=xloga` Differentiatingthroughoutw.r.tx, we GET `1/yd/DX="x"xx0+logaxx1=loga(DY)/(dx)=yloga=a^xloga(dy)/(dx)(x^x)=x^x(1+logx).d/dx(a^x)_2=a^2-loga` | |