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Differentiation of y = log sin cos x^3 |
Answer» Y=1/X -COSX SINX 3X ^2<br>1 wale ka 8+-0.16 hoga na<br>1 min ruko.<br>Ayush vo 1st wale ka 6 ± 0.16 ya 8 ± 0.16??<br>I have solved just now and I am getting the same answer your sir gotSorry for the inconvenience<br>Tnku for helping me in my homework manish and ayush ??<br>Hmmmmmmmmmmmmm<br>I will ask him<br>Yes it\'s ok never mind<br>Oooo.<br>It\'s ok<br>Ek baar sir se confirm kr lo tmhara answer abhi bhi sahi nahi hai ku ki cos^3(x) raheta tb 3 bahar aa kr multiply ho jata lakin tmhara question me cos x^3 hai or x jo hai wo ek angle hai or cos ka function hai isliye cos x^3 ka differentiation-sin x^3 hogaBecause differentiation of cos x is - sin x<br>Sorry according to your question my answer is incorrect because I have solved for cos cube x not for cos x to the power 3 so your sir is right<br>Meko bhi wai lag raha hai.<br>My sir told me it will be -3x^2 sin (x^3) cot ( cos (x^3) ) are u sure manish<br>Log ka function hai sin x cos^3x is liye uska differetation hoga 1/sin xcos^3xUske baad sin(x) ka differentiation hoga cos(x) or uske baas cos^3(x) ka hoga -2sin^2(x) uske baad usko simply solve kr do aa jayega answer<br>3xlog sin cos^2 hoga.<br>Plz bta.<br>Kya hoga. Aur kaise<br>-3sin(x).sec*2(x) | |