1.

Diffusion of He gas is

Answer»

4 TIMES faster than `CO_(2)`
4 times faster than `SO_(2)`
4 times faster than `NO_(2)`
4 times faster than `CiO_(2)`

Solution :(b) ACCORDING to Graham's law, `(r_(1))/(r_(2))=sqrt((M_(2))/(M_(1)))`
4=`sqrt((M_(2))/(4))rArr16=(M_(2))/(4)`
`M_(2)=64`


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