Dimension of a physical quantity is M^(a)L^(b)T^(c), then it is ......

1.	Dimension of a physical quantity is M^(a)L^(b)T^(c), then it is ......
Answer» VELOCITY if `a=1,B=0,c=-1` accceleration if `a=1,b=1,c=-2` force if `a=0,b=-1,c=-2` PRESSURE if `a=1,b=-1,c=-2` SOLUTION : `(A) M^(1)L^(0)T^(-1)` which is not dimension of velocity. (B) `M^(1)L^(1)T^(-2)` which is dimension of force but not ACCELERATION. (c) `M^(0)L^(-1)T^(-2)` Which is not dimension of force. (D) `M^(1)L^(-1)T^(-2)` which not dimension of pressure.

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