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InterviewSolution
| 1. |
Dimension of friction |
| Answer» The dimensional formula of coefficient of friction is given by,[M0\xa0L0\xa0T0]Where,\tM = Mass\tL = Length\tT = TimeDerivationCoefficient of friction (μ) = Frictional Force × [Normal Force]-1\xa0. . . . (1)Since, Force (F) = Mass\xa0× acceleration =\xa0Mass\xa0× velocity\xa0× [Time]-1And, velocity = Displacement\xa0× [Time]-1∴ The dimensions\xa0of Force = [M] × [LT-1]\xa0× [T]-1\xa0= [M1\xa0L1\xa0T-2] . . . . (2)On substituting equation (2) in equation (1) we get,Coefficient of friction (μ) = Frictional Force × [Normal Force]-1Or, μ = [M1\xa0L1\xa0T-2]\xa0× [M1\xa0L1\xa0T-2]-1\xa0= [M0\xa0L0\xa0T0].Therefore, the coefficient of friction is dimensionally represented as\xa0[M0\xa0L0\xa0T0]. | |