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Dimensional formula of self induction |
Answer» The magnetic flux is given byϕ=LIThe dimensional formula of self inductance,\xa0[L]=[BA]/[I]\u200b. . . . . .(1)Force,\xa0f=qvB[M1L1T−2]=[TA].[L1T−1].[B][B]=[M1T−2A−1][BA]=[M1L2T−2A−1]From equation (1), we get[ϕ]=[M1L2T−2A−2] | |