Dimensions of (L)/(RCV) are

1.	Dimensions of (L)/(RCV) are
Answer» `[A^(-1)]` `[A^(-2)]` `[A]` `[A^(2)]` Solution :`(L)/(R)` is the time constant of LR circuit, So `(L)/(R)` has the DIMENSION of time. `:.[(L)/(R)]= [T]` `:. "Charge" = "Capacitance" xx "Potential DIFFERENCE"` `Q= CV :. [CV]= [AT]` `:. [(L)/(RCV)]= [(T)/(AT)]= [(1)/(A)]= [A^(-1)]`

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