Dimensions of resistance are same as (where his Planck's constant and

1.	Dimensions of resistance are same as (where his Planck's constant and e is charge)
Answer» `(h)/(e)` `(h^(2))/(e)` `(h)/(e^(2))` `(h^(2))/(e^(2))` Solution :ACCORDING to Ohm.s LAW V=IR `"Resistance"= ("Potential difference (V)")/("current (I)")= [ML^(2)T^(-3)A^(-1)]/[A]= [ML^(2)T^(-3)A^(-2)]` Dimensions of Planck.s CONSTANT h= `[ML^(2)T^(-3)A^(-2)]` `:. (h)/(e^(2))= ([ML^(2)T^(-1)])/([AT]^(2))= [ML^(2)T^(-3)A^(-2)]`

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