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Direction cosines of the line `(x+2)/(2)=(2y-5)/(3),z=-1` are |
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Answer» The given line is , `(x+2)/(2)=(2y-5)/(3)=(z+1)/(0)` `(x+2)/(2)=(2(y-(5)/(2)))/(3)=(z+1)/(0)` `(x+2)/(2)=(y-(5)/(2))/(3/(2))=(z+1)/(0)` The direction cosines are `(2,(3)/(2),0)` |
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