Direction: Given below are two quantities named I and II. Based on the

1.	Direction: Given below are two quantities named I and II. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose among the possible answers.A train of 500 meters length can cross completely a platform of 1000 meters length in 5 min. Quantity I: What is the speed of the train in meters per second? Quantity II: A bicycle running in the same direction of the train can pass the train completely in 15 minutes then what was the speed of the bicycle in meters per sec?1. Quantity 1 > Quantity 22. Quantity 1 ≥ Quantity 23. Quantity 1 < Quantity 24. Quantity 1 ≤ Quantity 25. Quantity 1 = Quantity 2
Answer» Correct Answer - Option 3 : Quantity 1 < Quantity 2 Given: Length of train = 500 m Length of platform = 1000 m Time taken to cross a platform = 5 min Formula : Distance = Speed × Time The relative speed of two bodies with speed x m/sec and y m/sec, traveling in the same direction is (x – y) m/sec, where x > y. Calculation: Quantity I: (500 + 1000) = speed of train × 300 ⇒ 1500 = speed of train × 300 ⇒ speed of train = 5 m/s Quantity II: 15 minutes = 15 × 60 = 900 sec Let the speed of the bicycle = x m/sec Relative speed = (x – 5) m/sec Distance = Relative speed × Time 500 = 900 × (x – 5) ⇒ 5/9 = x – 5 ⇒ x = 5 + 5/9 ⇒ x = 50/9 m/sec ⇒ Speed of bicycle = 50/9 m/sec ∴ Quantity I < Quantity II

Direction: Given below are two quantities named I and II. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose among the possible answers.A train of 500 meters length can cross completely a platform of 1000 meters length in 5 min. Quantity I: What is the speed of the train in meters per second? Quantity II: A bicycle running in the same direction of the train can pass the train completely in 15 minutes then what was the speed of the bicycle in meters per sec?1. Quantity 1 > Quantity 22. Quantity 1 ≥ Quantity 23. Quantity 1 < Quantity 24. Quantity 1 ≤ Quantity 25. Quantity 1 = Quantity 2

Answer» Correct Answer - Option 3 : Quantity 1 < Quantity 2

Given:

Length of train = 500 m

Length of platform = 1000 m

Time taken to cross a platform = 5 min

Formula :

Distance = Speed × Time

The relative speed of two bodies with speed x m/sec and y m/sec, traveling in the same direction is (x – y) m/sec, where x > y.

Calculation:

Quantity I:

(500 + 1000) = speed of train × 300

⇒ 1500 = speed of train × 300

⇒ speed of train = 5 m/s

Quantity II:

15 minutes = 15 × 60 = 900 sec

Let the speed of the bicycle = x m/sec

Relative speed = (x – 5) m/sec

Distance = Relative speed × Time

500 = 900 × (x – 5)

⇒ 5/9 = x – 5

⇒ x = 5 + 5/9

⇒ x = 50/9 m/sec

⇒ Speed of bicycle = 50/9 m/sec

∴ Quantity I < Quantity II